0=-4.9t^2+24t+8

Solution for 0=-4.9t^2+24t+8 equation:

0=-4.9t^2+24t+8

We move all terms to the left:

0-(-4.9t^2+24t+8)=0

We add all the numbers together, and all the variables

-(-4.9t^2+24t+8)=0

We get rid of parentheses

4.9t^2-24t-8=0

a = 4.9; b = -24; c = -8;
Δ = b2-4ac
Δ = -242-4·4.9·(-8)
Δ = 732.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-\sqrt{732.8}}{2*4.9}=\frac{24-\sqrt{732.8}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+\sqrt{732.8}}{2*4.9}=\frac{24+\sqrt{732.8}}{9.8}
$